If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12x^2+0x-4=0
We add all the numbers together, and all the variables
12x^2+x-4=0
a = 12; b = 1; c = -4;
Δ = b2-4ac
Δ = 12-4·12·(-4)
Δ = 193
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{193}}{2*12}=\frac{-1-\sqrt{193}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{193}}{2*12}=\frac{-1+\sqrt{193}}{24} $
| 400=60x-2x^2 | | 12/6=8/y-1 | | x/3+4=16 | | 50000/x=500 | | (2x+1)=(3x-22) | | -11*11*8=x | | C=3,x^2+6= | | -4x+5-2=x | | .03x^2-8x+700=624 | | 11/30y=33/10 | | 3/5^2x=1 | | 12/6=8/y-1=y+1/2 | | f(×)=-0.2+5 | | .03x^2-8x=624 | | x^=51+14x | | 6-5=12-s | | 10+x=4+8 | | 8=2/7v | | F(-2)=x+6 | | 1=1/2(4y+2) | | 7(1.06^3x+1)=12 | | 19=4-x | | 8x+6=2x-16 | | (3x-5)^2+9(3×-5)+18=0 | | 7(1.063x+1)=12 | | Y=-0.08x^2+1.6x+10 | | 8=0.50/x | | 1/3(0)-1=y | | -14+10r=-3r | | 8(3x-8)=2(12+6) | | 5x+25=85 | | -5+4t=-7t |